15,399,959 members
See more:
main.cpp

```<pre>#include <iostream>
#include <cmath>
#include "jsdbejbfkejfb.h"
#include <regex>

void idkwwt item: ";
std::cin >> input_string;
valid_input = is_integer(input_string);
// if input is not an integer, print an error message
if (valid_input == false) {
std::cout << "Enter an integer!\n";
} else {  // if it is an int, check whether in range
input = std::stoi(input_string);  // convert to int
if (input >= 1 && input <= menu_items) {
valid_input = true;
} else {
std::cout w
switch (input) {
case 1:
voltage_divider_Calc();
break;
case 2:
curra
}

sts----------------------\n";
}

void goa
d
std::cout << "\n>> Current Divider Calculator\n";
std::cout << "\nSome code here does something useful\n";
go_back_to_main();
}

std::cout << "\n>&gs
}```

Volw.h
```#ifndef Voltage_H
w
float _Vs;
float _Vout;

};

#endif```

qhi.cpp

```#include "Voltage.h"

void
Volzzzzzzzzzzzz
}

float
Voltage::get_Vout ()
{
_Vout = (_Vs * _R2) / (_R1 + _R2);
return _Vout;
}```
w

What I have tried:

Ive tried repeating the calculation with different numbers but its the same output so im guess it is not doing the calculation
Posted
Updated 8-Jan-22 5:17am
v5
k5054 7-Dec-21 17:18pm

I'll give you a clue to help with the debuging: If you put a break point at `Voltage::voltage_divider_Calc()`, what are the values of the voltage member variabes _R1, _R2, and _Vs? Why?
k5054 7-Dec-21 17:37pm

Oops, you're right (there probably should be, though hint hint). I guess I meant Voltage::get_Vout()

## Solution 1

Compiling does not mean your code is right! :laugh:
Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.

So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.

Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:
```Input   Expected output    Actual output
1            2                 1
2            4                 4
3            6                 9
4            8                16```
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
C
```int Double(int value)
{
return value * value;
}```

Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on the first line of the method, and run your app. When it reaches the breakpoint, the debugger will stop, and hand control over to you. You can now run your code line-by-line (called "single stepping") and look at (or even change) variable contents as necessary.
Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
Hopefully, that should help you locate which part of that code has a problem, and what the problem is.
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!

## Solution 2

I see two problems with your code, one of which you have asked about. In `voltage_divider_Calc` you have a `voltage` object and you call its `get_Vout` method BUT you did not set its members so it can not give you a valid result.

The other problem is if you select return to the main menu you call the function `go_back_to_main_menu` which essentially restarts the menu. The problem with that is you have introduced recursion into your program. It will continue until exit is selected and then you call `exit()`. That is not recommended practice at all. You need to make your main menu a top level function that loops continuously until you want to exit out of the program because that will give you an opportunity to release any resources you have allocated. Calling `exit` does allow that.
Member 15459232 7-Dec-21 17:28pm

what do you mean by you did not set its members can you clarify please
Rick York 7-Dec-21 18:08pm

Look at the implementation of voltage_divider_Calc(). It acquires input for three local variables and then it does nothing with those values. The voltage object has its get_Vout() method called but the object's members are not set to the values that were input.

## Solution 3

You create a Voltage object, but at that point none of its members have any values. You then call `cin` to get values for the local variables `_R1`, `_R2` and `_Vs`. You then call the `get_Vout` member function of your `Voltage` object, to calculate something. But since that object has not been initialised with any values it has nothing to work with so the answer will most likely be zero, or some random number.
C++
```Voltage voltage;
std::cout << "\n Enter a value for top resistor R1\n";
std::cin >>  (_R1);
std::cout << "\n Enter a value for bottom resistor R2\n";
std::cin >>  (_R2);
std::cout << "\n Enter a value for the source voltage Vs\n";
std::cin >>  (_Vs);
float Vout = voltage.get_Vout();
```

You need to create the `Voltage` object after you have got the input values. You then need to call the setter methods (`set_R1` etc.) to set those values into the object before you make the call to `get_Vout`.