C / C++ / MFC

It is undefined behaviour because you have used wrong format specifier. Use %u instead of %d for unsigned int. like :

unsigned int a=-26;
printf("\n%u",a);

If any argument is not the correct type for the corresponding conversion specification, the behavior is undefined.

Rick York wrote:

It may not be what you want but it is as expected.

samzcs wrote:

It works.

void funcA( unsigned int * dtc, unsigned int* status)
{
   int rval;
   unsigned int lstatus; 
   rval = funcB(dtc, &lstatus);
   .....
}
 
int funcB(unsigned int *idtc, unsinged int* istatus ) {
   *istatus = XXX;
}

vector<vector<double>> _muPop(row, vector<double>(col));

#include <vector>
#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

class Matrix
{
  int R, C;
  vector <vector <int> > m;
public:
  Matrix(int r, int c):R(r),C(c)
  {
    for (int r = 0; r<R; ++r)
    {
      m.push_back(vector <int >());
      for (int c = 0; c<C; ++c)
        m[r].push_back(c+1);
    }
  }
  friend ostream & operator << (ostream & os, const Matrix & mat);
};


ostream & operator << (ostream & os, const Matrix & mat)
{
  for (int r = 0; r<mat.R; ++r)
  {
    for (int c = 0; c<mat.C; ++c)
      os << setw(4) << mat.m[r][c];
    os << endl;
  }
  return os;
}

int main(int argc, char * argv[])
{
  int rows=1, cols=1;

  if ( argc >= 3)
  {
    rows = stoi(argv[1]);
    cols = stoi(argv[2]);
  }

  Matrix m(rows,cols);
  cout << m << endl;
}