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7 out of 10.. Could be better..
The signature is in building process.. Please wait...
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Makes you think; got all of them correct.
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The answer for question 2 (answer: 20) is questionable. How can the exact minutes be determined using an average speed?
TOMZ_KV
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You don't get jokes either? 
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are these not real test question? Tell me about it. 
TOMZ_KV
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Why would that be questionable? How do you think the speedometer calculated the average speed?
Obviously it took the total 6 km and divided it by the total time of 1/3 hour to arrive at 18 km/h.
The good thing about pessimism is, that you are always either right or pleasently surprised.
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Average doesn't mean approximate...
The speeds and times did add up suspiciously neatly.
Iain.
I am one of "those foreigners coming over here and stealing our jobs". Yay me!
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You are correct. I got the idea. The average speed by speedometer was based on the actual time and distance she traveled.
TOMZ_KV
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I scored 100% 
Used a calculator for two of the three Mount ... questions because I was too lazy to calculate it on paper. Did the rest in the head.
The good thing about pessimism is, that you are always either right or pleasently surprised.
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100%
Will Rogers never met me.
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ok how did I miss 2.
I think the answer to # 7 is wrong.
I chose what they said was the correct answer but..
You could not Physically have 6 people coming in at the same time.
4 at the most.
I think # 9 was wrong also.
I could have sworn I chose the smallest number.
Is 26.5 larger or smaller than 26.58 ?
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On #7, that's a very astute observation! The obvious solution, and the one most of us used and were scored as correct, is that all three compartments are full. But of the three, only two will be entering; one will be filled with people leaving. Your answer is technically correct in a real world sense, but when has a mathematician concerned himself with reality? 
On #9, I don't know which you picked, but 26.58 is clearly 0.08 larger than 26.5. It is normal practice to omit trailing zeroes unless a fixed width format is specified.
Will Rogers never met me.
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I picked "A" but without looking at the chart again I can not be sure what the numbers were.
If I remember correctly the last 2 in the chart were larger than the first 2.
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Actually none of the answers were correct, not even mathematically, unless the question had been "how many people could pass the door in 30 minutes on average?"
My point is that if people start entering at T0=0 no one is in either compartment, and it will take about the time of half a rotation (~7.5s) before the first pair of persons will emerge on the other side. After that 2 persons will exit the door every 5 seconds (1/3rd of the time of a full rotation). At T1=30minutes, 30*60=1800 seconds have passed, but only 1792.5 seconds have passed since the emergence of the first pair, so only 358 pairs will have time to pass after the first one (taking 358*5s=1790s), for a total of 718 people, not 720!
I am well aware that this answer is even less practically useful than 720, but if this is supposed to be a math test, such a subtlety should be considered!
A similar, but less complex question would be this:
You want to build a fence that is 30m long, and you need to put a fence post every 2m. How many fence posts do you need?
This is a typical "one-off" question, where you need to consider the exact starting and stopping conditions to make sure your count is not one off the actual number. It should be well known to programmers too, when it comes to counting loop iterations!
GOTOs are a bit like wire coat hangers: they tend to breed in the darkness, such that where there once were few, eventually there are many, and the program's architecture collapses beneath them. (Fran Poretto)
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I agree there was a logistical component to the problem that I pondered as well, while I was doing the math. I pondered that 2 people would be trapped when it stopped, but that would be if the were 4 divisions, with 3, they'd still be able to squeeze out single file, so I went with the accepted answer.
Psychosis at 10
Film at 11
Those who do not remember the past, are doomed to repeat it.
Those who do not remember the past, cannot build upon it.
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I am a pusillanimous pettifogger.
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100% no calculator or pen and paper, cmon guys this is primary school stuff.
We can’t stop here, this is bat country - Hunter S Thompson RIP
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Scored 90/100. 
(Inspite of using the calculator after Q5  )
Piyush K Singh
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It's an OO world.
public class Sander : Lazy<Person>{
public void DoWork(){ throw new NotImplementedException(); }
}
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9/10, but surely the right answer here is 8am? 18km at 1.5 km/h will take 12 hours?
The Gotemba walking trail up Mount Fuji is about 9 kilometres (km) long. Walkers need to return from the 18 km walk by 8pm. Toshi estimates that he can walk up the mountain at 1.5 kilometres per hour on average, and down at twice that speed. These speeds take into account meal breaks and rest times. Using Toshi’s estimated speeds, what is the latest time he can begin his walk so that he can return by 8pm?
10am
11am
12pm
1pm
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Sorry, missed "down at twice that speed..." Oops...
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The text was a bit confusing as the "18km" imply the total of both ways, but each half was to be calculated differently.
Like pretty much every other question here it was more of a reading comprehension test than maths. 
GOTOs are a bit like wire coat hangers: they tend to breed in the darkness, such that where there once were few, eventually there are many, and the program's architecture collapses beneath them. (Fran Poretto)
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I think you are replying to the wrong message. I never said anything about what you said...
It's an OO world.
public class Sander : Lazy<Person>{
public void DoWork(){ throw new NotImplementedException(); }
}
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Thanks for posting this, it was a welcome distraction. Of course the 10/10 helped (yes, I used a calculator, why do the heavy lifting yourself if you have a crane handy )
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