15,877,591 members
See more:
For exp we have this sequence of numbers:
10 25 50 50
p(10) = 25% and 10!= p(10) =25 so false
p(25) = 25% and 25 == 25 so true
p(50) = 50% and 50 == p(50) =50 true

the number of true is 2 so p(true) is 75%

i want to print 75% (the number of true, i mean count the proba when the number equal its probability of apperance in the sequence )

here is my essaie :

What I have tried:

Java
```import java.util.*;
import java.io.*;
import java.math.*;

/**
* Auto-generated code below aims at helping you parse
* the standard input according to the problem statement.
**/
class proba {

public static void main(String args[]) {
Scanner in = new Scanner(System.in);
int s=0;
int p=1;
int ss=0;
int N = in.nextInt();
List<Integer> l = new ArrayList<>();
for (int i = 0; i < N; i++) {
int v = in.nextInt();
}
ListIterator<Integer> it = l.listIterator();
while(it.hasNext()){
Integer i = it.next();
while(it.hasNext()){
if(it.equals(i))
s++;
}

p=(s/N)*100;
if (p == i)
ss++;

}

System.out.print((ss/N)*100);

}
}```
Posted
Updated 6-Dec-17 22:12pm
v2
OriginalGriff 7-Dec-17 4:06am
And?
What is the problem?
What does it do that you didn't expect, or not do that you did?
What help do you need?
CodeWraith 7-Dec-17 4:27am
the number of true is 2

That explains everything.

Solution 1

To compute the probability of every number you must count its occurrences in the list. The algorithm is simpler provided the list is ordered.