Click here to Skip to main content
15,389,833 members
Please Sign up or sign in to vote.
1.00/5 (1 vote)
See more:
include "baglan.php";
if (isset($_POST["br"]) && isset($_POST["ad"]) && isset($_POST["yz"]) && isset($_POST["yv"]) && isset($_POST["ft"]) && isset($_POST["st"]) && isset($_POST["im"])) {
$br = $_POST["br"];
$ad = $_POST["ad"];
$yz = $_POST["yz"];
$yv = $_POST["yv"];
$ft = $_POST["ft"];
$st = $_POST["st"];
$im = $_POST["im"];

if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);

$sql = "INSERT INTO `kid`(`id`, `kimg`, `ad`, `yazar`, `yv`, `ft`, `stok`, ) VALUES ('$br','$im','$ad','$yz','$yv','$ft','$st')";

if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error:
" . $conn->error;


What I have tried:

$sql = "INSERT INTO `kid`(`id`, `kimg`, `ad`, `yazar`, `yv`, `ft`, `stok`, ) VALUES ('$br','$im','$ad','$yz','$yv','$ft','$st')";
Updated 22-Jun-22 9:25am

Hi Most probably only one comma....

INSERT INTO `kid`(`id`, `kimg`, `ad`, `yazar`, `yv`, `ft`, `stok`,) VALUES ('$br','$im','$ad','$yz','$yv','$ft','$st')";
INSERT INTO `kid`(`id`, `kimg`, `ad`, `yazar`, `yv`, `ft`, `stok`) VALUES ('$br','$im','$ad','$yz','$yv','$ft','$st')";

focus on `stok`,) VALUES . Delete that comma and most probably you solved it ;)
0x01AA 22-Jun-22 14:57pm
Btw. take care about SQL injection ;)
And again, the reason why ... Never concatenate strings to build a SQL command. It leaves you wide open to accidental or deliberate SQL Injection attack which can destroy your entire database. Always use Parameterized queries instead.

When you concatenate strings, you cause problems because SQL receives commands like:
SELECT * FROM MyTable WHERE StreetAddress = 'Baker's Wood'
The quote the user added terminates the string as far as SQL is concerned and you get problems. But it could be worse. If I come along and type this instead: "x';DROP TABLE MyTable;--" Then SQL receives a very different command:
SELECT * FROM MyTable WHERE StreetAddress = 'x';DROP TABLE MyTable;--'
Which SQL sees as three separate commands:
SELECT * FROM MyTable WHERE StreetAddress = 'x';
A perfectly valid SELECT
A perfectly valid "delete the table" command
And everything else is a comment.
So it does: selects any matching rows, deletes the table from the DB, and ignores anything else.

And in a login system? That's just asking for trouble as I don't even have to have to register with you to do it!

So ALWAYS use parameterized queries! Or be prepared to restore your DB from backup frequently. You do take backups regularly, don't you?

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

  Print Answers RSS
Top Experts
Last 24hrsThis month

CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900