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I work on sql server 2019 i face issue i need to give unique number to every group of numbers without using string aggreagte or stuff

original table as below :

create table #parts
     (
     PartNumber varchar(50),
     PartValue int,
     UniqueNumber int
     )
     insert into #parts(PartNumber,PartValue,UniqueNumber)
     values
     ('P1',1,NULL),
     ('P1',2,NULL),
     ('P1',3,NULL),
     ('P1',4,NULL),
     ('P2',1,NULL),
     ('P2',2,NULL),
     ('P3',1,NULL),
     ('P3',2,NULL),
     ('P3',3,NULL),
     ('P4',1,NULL),
     ('P4',2,NULL),
     ('P4',3,NULL),
     ('P5',1,NULL),
     ('P5',2,NULL)


expected result as below


PartNumber	PartValue	UniqueNumber
P1	1	1
P1	2	1
P1	3	1
P1	4	1
P2	1	2
P2	2	2
P3	1	3
P3	2	3
P3	3	3
P4	1	3
P4	2	3
P4	3	3
P5	1	2
P5	2	2


What I have tried:

SELECT
   p.PartNumber,
   p.PartValue,
   p2.Parts,
   NewUniqueNumber = DENSE_RANK() OVER (ORDER BY p2.Parts)
 FROM #parts p
 JOIN (
     SELECT
       p2.PartNumber,
       STRING_AGG(p2.PartValue, ',') WITHIN GROUP (ORDER BY p2.PartValue) Parts
     FROM #parts p2
     GROUP BY
       p2.PartNumber
 ) p2 ON p2.PartNumber = p.PartNumber;
Posted
Updated 24-Jul-22 23:05pm
Comments
ahmed_sa 25-Jul-22 3:06am    
the goal mfrom asking question is to get result above without string aggreagte or comma separated
suppose i have
p1 1,2,3
p2 2,2,2
both p1 and p2 both have same count and same sum
so are there are another solution without
using string aggregate

1 solution

Try this:

SQL
SELECT T.PartNumber, T.PartValue,T.CNT, DENSE_RANK() OVER(ORDER BY T.CNT) AS UniqgNo
FROM 
(
  SELECT *, COUNT(*) OVER(PARTITION BY PartNumber) AS CNT
  FROM PP
) AS T


SQL Server 2019 | db<>fiddle[^]

Note: Replace [*] with column names you want to get in subquery. I was lazy ;)
 
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