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If I use :
CString tempo =_T("0.0057");
double d_tempo = _ttof(tempo);


d_tempo = 0.0000 so _ttof is wrong

What I have tried:

I tried with atof but it's the same thing
Posted
Updated 2-Aug-22 9:22am
Comments
Richard MacCutchan 2-Aug-22 11:49am    
I just tried that and it works perfectly, as it probably does in thousands of applications around the world. There is some information that you are not showing us.
0x01AA 2-Aug-22 14:52pm    
Are you working in debugger and you don't use d_tempo after that conversion? E.g. my compiler would optimize that in a way I can't trust then the result in the debugger. To avoid that I simply add code like this: if (d_tempo > 0.0);
Member 14594285 3-Aug-22 3:28am    
My result is d_tempo = 0.0000 and not 0.0057
0x01AA 3-Aug-22 4:34am    
Yes, I understand that. But how you inspect d_temp? With debugger? And if yes, there is a chance that the compiler does 'optimize away' the assignement to d_temp when you don't use d_temp after assignement.
Again: To be sure that it is not 'compiler optimation side effect' do something like

CString tempo =_T("0.0057");
double d_tempo = _ttof(tempo);
if (d_tempo > 0.0);


Of course if you use d_tempo anyhere else the above is not necessary...

Just like Richard, it works without changing anything. Since the function expects pointers, the alternatives would be:
C++
CString tempo = _T("0.0057");
double d_tempo = _ttof(tempo.GetBuffer());

wchar_t const* tempo2 = _T("0.0057");
double d_tempo2 = _ttof(tempo2);
 
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You have some string issue with unicode. Read the Microsoft documentation.

You may use the define
_UNICODE
or use
C++
wcstod()
 
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